Lemma:
4 = 5
Bewijs:
16 - 36 = 25 - 45
<=> 16 - 36 + 4,5² = 25 - 45 + 4,5²
<=> 4² - 2*4,5*4 + 4,5² = 5² - 2*4,5*5 + 4,5²
<=> (4 - 4,5)² = (5 - 4,5)²
<=> 4 - 4,5 = 5 - 4,5
<=> 4 = 5
Wat te bewijzen was.
Wiskunde regels
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Lemma:
5 = 7 Bewijs: 5 + 2 = 7 <=> 5 * (5 + 2) = 5 * 7 <=> 25 + 10 = 35 <=> 25 + 10 - 35 = 35 - 35 <=> 25 + 10 - 35 = 35 - 35 - 14 + 14 <=> 25 + 10 - 35 = 35 + 14 - 49 <=> 5 * (5 + 2 - 7) = 7 * (5 + 2 - 7) <=> 5 = 7 Wat te bewijzen was. |
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@0 Lemma: 4 = 5 Bewijs: 16 - 36 = 25 - 45 <=> 16 - 36 + 4,5² = 25 - 45 + 4,5² <=> 4² - 2*4,5*4 + 4,5² = 5² - 2*4,5*5 + 4,5² <=> (4 - 4,5)² = (5 - 4,5)² <=> 4 - 4,5 = 5 - 4,5 <=> 4 = 5 Wat te bewijzen was. |
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@1 Lemma:5 = 7 Bewijs: 5 + 2 = 7 <=> 5 * (5 + 2) = 5 * 7 <=> 25 + 10 = 35 <=> 25 + 10 - 35 = 35 - 35 <=> 25 + 10 - 35 = 35 - 35 - 14 + 14 <=> 25 + 10 - 35 = 35 + 14 - 49 <=> 5 * (5 + 2 - 7) = 7 * (5 + 2 - 7) <=> 5 = 7 Wat te bewijzen was. Delen door 0 |
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x = 0.999...
10x = 9.999... 10x-x = 9.999...-0.999... 9x = 9 x = 1 0.999... = 1 of 1/3 = 0.333... 3/3 = 0.999... 1 = 0.999... |
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dus wat jij wilt zeggen is dat 1/oneindig = 0 ??? :O :O
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lim 1/n = 0 n->infDus, 1/inf is idd 0. |
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@6 lim 1/n = 0 n->infDus, 1/inf is idd 0. zo werkt 'n bewijs niet |
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Ok, dat is geen bewijs, maar gewoon een manier van opschrijven.
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@4 x = 0.999...10x = 9.999... 10x-x = 9.999...-0.999... 9x = 9 x = 1 0.999... = 1 of 1/3 = 0.333... 3/3 = 0.999... 1 = 0.999... :/ |
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@9 @4 x = 0.999...10x = 9.999... 10x-x = 9.999...-0.999... 9x = 9 x = 1 0.999... = 1 of 1/3 = 0.333... 3/3 = 0.999... 1 = 0.999... :/ http://en.wikipedia.org/wiki/0.999...%3D1 |
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